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uniqueByRight

TS JS Deno

Returns all unique values of an array, based on a provided comparator function, starting from the right.

Use Array.prototype.reduceRight() and Array.prototype.some() for an array containing only the last unique occurrence of each value, based on the comparator function, fn. The comparator function takes two arguments: the values of the two elements being compared.

typescript
const uniqueByRight = (arr: any[], fn: Predicate) =>
  arr.reduceRight((acc, v) => {
    if (!acc.some((x: any) => fn(v, x))) acc.push(v);
    return acc;
  }, []);
typescript
uniqueByRight(
  [
    { id: 0, value: "a" },
    { id: 1, value: "b" },
    { id: 2, value: "c" },
    { id: 1, value: "d" },
    { id: 0, value: "e" },
  ],
  (a: any, b: any) => a.id == b.id
); // [ { id: 0, value: 'e' }, { id: 1, value: 'd' }, { id: 2, value: 'c' } ]