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maxN

TS JS Deno

Returns the n maximum elements from the provided array. If n is greater than or equal to the provided array's length, then return the original array (sorted in descending order). The default order for sorting is desc, pass -1 for asc

Use Array.prototype.sort() combined with the spread operator (...) to create a shallow clone of the array and sort it in descending order. Use Array.prototype.slice() to get the specified number of elements. Omit the second argument, n, to get a one-element array.

typescript
type SortOrder = 1 | -1;
const maxN = (arr: any[], n = 1, order: SortOrder = 1) =>
  [...arr].sort((a, b) => order * (b - a)).slice(0, n);
typescript
maxN([1, 2, 3]); // [3]
maxN([1, 2, 3], 2); // [3,2]
maxN([1, 2, 3], 2, -1); // [1,2]
maxN([1, 2, 3], 1, -1)[0]; // 1