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filterNonUniqueBy

TS JS Deno

Filters out the non-unique values in an array, based on a provided comparator function.

Use Array.prototype.filter() and Array.prototype.every() for an array containing only the unique values, based on the comparator function, fn. The comparator function takes four arguments: the values of the two elements being compared and their indexes.

typescript
const filterNonUniqueBy = <T = any>(
arr: T[],
fn: (obj1: T, obj2: T, index1: number, index2: number) => any
) => arr.filter((v, i) => arr.every((x, j) => (i === j) === fn(v, x, i, j)));
typescript
filterNonUniqueBy(
[
{ id: 0, value: "a" },
{ id: 1, value: "b" },
{ id: 2, value: "c" },
{ id: 1, value: "d" },
{ id: 0, value: "e" },
],
(a, b) => a.id == b.id
); // [ { id: 2, value: 'c' } ]