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union

TS JS Deno

Returns every element that exists in any of the two arrays once.

Create a Set with all values of a and b and convert to an array.

typescript
const union = (a: any[], b: any[]) => Array.from(new Set([...a, ...b]));
typescript
union([1, 2, 3], [4, 3, 2]); // [1, 2, 3, 4]