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intersection

TS JS Deno

Returns a list of elements that exist in both arrays.

Create a Set from b, then use Array.prototype.filter() on a to only keep values contained in b.

typescript
const intersection = (a: any[], b: any[]) => {
const s = new Set(b);
return [...new Set(a)].filter((x) => s.has(x));
};
typescript
intersection([1, 2, 3], [4, 3, 2]); // [2, 3]