Skip to main content


TS JS Deno

Compares two objects to determine if the first one contains equivalent property values to the second one.

Use Object.keys(source) to get all the keys of the second object, then Array.prototype.every(), Object.hasOwnProperty() and strict comparison to determine if all keys exist in the first object and have the same values.

const matches = (obj: AnyObject, source: AnyObject) =>
(key) => obj.hasOwnProperty(key) && obj[key] === source[key]
matches({ age: 25, hair: "long", beard: true }, { hair: "long", beard: true }); // true
matches({ hair: "long", beard: true }, { age: 25, hair: "long", beard: true }); // false