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TS JS Deno

Chunks an array into smaller arrays of a specified size.

Use Array.from() to create a new array, that fits the number of chunks that will be produced. Use Array.prototype.slice() to map each element of the new array to a chunk the length of size. If the original array can't be split evenly, the final chunk will contain the remaining elements.

export const chunk = (arr: any[], size: number) =>
Array.from({ length: Math.ceil(arr.length / size) }, (_: any, i: number) =>
arr.slice(i * size, i * size + size)
chunk([1, 2, 3, 4, 5], 2); // [[1,2],[3,4],[5]]