orderByFunc

Returns a sorted array of objects ordered by properties and orders.

Uses Array.prototype.sort(), Array.prototype.reduce() on the props array with a default value of 0. Uses compare function callback fn to compare result based on the prop type.

typescript

export const orderByFunc = <T = AnyObject>(
  arr: T[],
  props: (keyof T)[],
  fn: Function
) =>
  [...arr].sort((a, b) =>
    props.reduce((acc, prop, i) => {
      if (acc === 0) {
        const [p1, p2] = [a[prop], b[prop]];
        acc = fn(p1, p2, prop);
      }
      return acc;
    }, 0)
  );

typescript

const users = [
  { name: "fred", age: 48 },
  { name: "barney", age: 36 },
  { name: "fred", age: 40 },
];
orderByFunc(
  users,
  ["name", "age"],
  <T extends string | number>(p1: T, p2: T, prop: string) => {
    if (prop === "name") return String(p1).localeCompare(String(p2)); // asc
    if (prop === "age") return Number(p2) - Number(p1); // desc
  }
); // [ { name: "barney", age: 36 }, { name: "fred", age: 48 }, { name: "fred", age: 40 }];